An actual random thought:
I can't unclasp my hands.
I can't unclasp my hands.
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Sorry about the delay, Daniel. I'm in the fever of preparing my business for its move to Texas, and it's labor intensive to reformat the debate to this platform. As no one (until you just now) has expressed interest in it, I decided to put it on the backburner until I reach the Land of the Free. However, I'll start trying to work the reformatting into my routine . . .
LOVE your new picture!!!
OK, I'll wait on pins and needles. If you were to move closer to Austin, you would have help from @cnystrom and myself.
I have the exact opposite expectations. If Trump wins, the snowflakes will get completely unhinged. Recall Hillary's remark about civility, where she said that they cannot be civil if they are not the ones in power.
Thanks, Daniel. We are first making a temporary move to Tarrant County for Holly Hannah to finish high school in 2022, but after that Llano is still very much an option, and then I'd only be about an hour from y'all!
You do? Thanks!
Oh yeah!
When he spotted a billboard for Denny's
Bacon and Eggs for half price
How could he resist such an offer?
He really needed something to munch
Cheeseburger please do not get angry
He'll even be back here for lunch.
It's such a polygamous love song!
I can wear my shirt as pants.
I vote that we sing that at our next retreat.
OK, so the answer is 781.
I just discovered an interesting numerical pattern.
1 *100 + 25 = 5^3
1 + 5^1 = 6 and 6 *100 +25 = 5^4
1 + 5^1 + 5^2 = 31 and 31*100 + 25 = 5^5
1+ 5^1 + 5^2 + 5^3 = 156 and 156* 100 + 25 = 5^6
1+5^1 + 5^2 + 5^3 + 5^4 = 781 and 781 * 100 + 25 = 5^7
1 + 5 + 25 + 125 + 625+ 3125 = 3906 and 3906 * 100 + 25 = 5^8
1 + 5 + 25 + 125 + 625 +3125+ 15625 = 19531 and 1953125 = 5^9
1+5+25+125+625+3125+15625+ 78125 = 97656 and 9765625 = 5^10
1+5+25+125+625+3125+15625+78125+390625 = 488281 and 48828125 = 5^11
Basically:
n
∑ [ 5^k ] = (5^(n+3) - 25) / 100
k = 0
So there are 2,441,406 zeros at the end of (5^10)!
Math is SO fun!
1 *100 + 25 = 5^3
1 + 5^1 = 6 and 6 *100 +25 = 5^4
1 + 5^1 + 5^2 = 31 and 31*100 + 25 = 5^5
1+ 5^1 + 5^2 + 5^3 = 156 and 156* 100 + 25 = 5^6
1+5^1 + 5^2 + 5^3 + 5^4 = 781 and 781 * 100 + 25 = 5^7
1 + 5 + 25 + 125 + 625+ 3125 = 3906 and 3906 * 100 + 25 = 5^8
1 + 5 + 25 + 125 + 625 +3125+ 15625 = 19531 and 1953125 = 5^9
1+5+25+125+625+3125+15625+ 78125 = 97656 and 9765625 = 5^10
1+5+25+125+625+3125+15625+78125+390625 = 488281 and 48828125 = 5^11
Basically:
n
∑ [ 5^k ] = (5^(n+3) - 25) / 100
k = 0
So there are 2,441,406 zeros at the end of (5^10)!
Math is SO fun!
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So the question is, why are there 1+5+25+125+625 zeros at the end of (5^5)!
@FollowingHim , I hope your son can figure that one out.
@FollowingHim , I hope your son can figure that one out.
My son that's most keen on maths is still only 7 years old, so I think the question is a bit beyond him.
Because 1, 5, 25, 125 and 625 are 5 to the 1st, 2nd, 3rd, 4th and 5th power.
I feel as much like I did yesterday as I do today.
I agree!
But first we'd need to define randomnality.
But first we'd need to define randomnality.